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(a) [He] 2s1,  the atom is lithium (3Li).(b) [Ne] 3s2 3p3, the atom is phosphours (15P).(c) [Ar] 4s2 3d1, the atom is scandium ( 21Sc).
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If potential at centre is zero, thenV1 +V2+V3 +V4 = 0
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Let us denote by X, the number of defective bulbs. Clearly X can take the values 0, 1, 2, 3, 4.
P(X = 0) = (no defective bulb) = P(all 4 goods ones)
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Radius of a nucleus of mass number A is given by,                         R =R0 
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Given, charge density =  
Radius and length of the cylindrical surface are r and l respectively.
Charge enclosed by the cylindrical surface =  l
Now, using
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Find CBSE, ICSE State Boards Textbook Solutions of Class 8 to 12 of all subjects. Read NCERT Textbooks Questions and Answers & Find Previous year solved papers.
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Given, a parallel plate capacitor is charged to a potential difference V. If the distance between the plates is doubled then,i) Electric field in between the pl
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The given differential equation is          3ex tan y dx + (1 – ex) sec2y dy = 0or    
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CBSE NCERT solutions for Class 11.Get free online study material for Class 11.Find NCERT solutions textbook questions and answers and download NCERT books from Zigya Book-Store.
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The velocity of boat is 18 km/hr in N-W direction and shore line makes angle 15° with S of W. Therefore the velocity vector of boat subtends an angle of 60°
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The importance of pipeline:

(i)Pipeline transport network is a new arrival on the transportation map of India. In the past, these were used to transport water to cities and industries.

(ii)Now, these are used for transporting crude oil, petroleum products and natural gas from oil and natural gas fields to refineries, fertilizer factories and big thermal power plants.

(iii)Solids can also be transported through a pipeline when converted into slurry.

(iv)The far inland locations of refineries like Barauni, Mathura, Panipat and gas based fertilizer plants could be thought of only bec

According to de-Broglie hypothesis, a stationary orbit is the one that contains an integral number of de-Broglie waves associated with the revolving electron.
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We are all living in the modern world. It is full of insecurity, fear, war, worry and stress. We have lost all our peace of mind. We can be butchered within mom
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For square planar shape, the hybridisation is dsp2. Hence the unpaired electrons in 5d orbital pair up to make one d orbital empty for dsp2 hybridisation.
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CBSE NCERT Solutions Resource Centre For Class 8 to 12. Download solved CBSE previous year papers, Solved sample papers, Pre-board papers. Students can download NCERT solutions for Class 8 to 12 - Zigya.

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Sn = 3n2 –4n⇒ Sn – 1= 3 (n – 1)2 –4 (n – 1)∴ Sn – Sn –1 = (3n2 – 4n) – {3(n – 1)2 – 4 (n –1)}⇒ an = (3n2 – 4n) – {3(

(Get CBSE, ICSE, and all State Boards textbook solutions for all subjects Class 8 to 12. You can also get CBSE solved papers of the previous year from here! You can also prepare for SSC. Can also test SSC, and find the SSC Resource Centre! You can get resources online for free for NEET, NEET's previous year solved paper, and JEE, JEE Previous year solved papers! Students can also find the previous year's papers etc. This is an organization related to the education sector! So